Question

0.1 the current 'I' through a resistor
is increased by 100%, (assume that
temprature remains unchanged) then
find the increase in power dissipated​

Answer 1

Answer:

The increase in power dissipated is 300%

Explanation:

Power is

${i}^{2} r$

initially

As new current is 2i

Hence new power is

$(2i)^{2} r$

So new power is 4 times original power hence Change in Power is 3 times original Power

Answer 2

Explanation:

Let the original value of current is I ampere.

The new value of current I′=I+100%I=2I.

Now, the new power P′=I′2

R=4I

R=4P.

So, the change in power = P′−P=3P

Therefore, the change in power in terms of percentage is 300%.

Hence, the increase in power dissipated will be 300%.