0.10)Find the value of k for which given equation has real and equal roots 1) (k-12)x2+2(k-12)x+2=0
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for real and equal root b^2 - 4ac = 0
Therefore, (2k-24)^2 - 4*(k-12)*2 = 0
(4k^2 - 96k+576) - (8k - 96) = 0
4k^2 - 104k+672 = 0
k^2 - 26k + 169 = 0
(k-13)^2 = 0
k = +13 , -13.
Step-by-step explanation:
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