Question

0 10 The class mark of a distribution area
6, 10, 14, 18, 22,26,30
i)
find the class size
ii) find the fiast class internal​

Answer 1

Answer:

hi everyone have a nice day

Answer 2

Answer:

We observe that 10 - 6 = 4, 14 - 10 = 4 …& so one.

Hence, class size is 4.

Now, the difference between the values of two consecutive class marks is 4, therefore we subtract 4/2 = 2 from each class mark to get the lower limit of the corresponding class interval and add 5 to each class mark to get the upper limit.

Thus, the class intervals are

4 - 8

8 - 12

12 - 16

16 - 20

20 - 24

24 - 28

28 - 32