Question

0-11 ABC is a night angled triangle in which angle A = 90' and AB - AC Find angle B and angle c​

Answer 1

Answer:

Draw a line EF perpendicular to AB and CD passing through M

In △BME

∠BME+∠MBE+∠BEM=180

∘

(Angle sum proprerty)

∠BME+35

∘

+90

∘

=180

∘

∠BME=180

∘

−125

∘

∠BME=45

∘

In △DMF

∠DMF+∠MDF+∠MFD=180

∘

(Angle sum property )

∠DMF+75

∘

+90

∘

=180

∘

∠DMF=180

∘

−165

∘

∠DMF=15

∘

x=∠DMF+∠BME+∠EMF

x=15

∘

+45

∘

+180

∘

x=240

∘

Answer 2

Answer:

two sides equl means two angkes equl.

means remaining angles are equal

by angle sum property

sum of all the angkes is 180

180-90 = 90

means sum of remainning two angles should be 90 and both should be eql

it is possible only if both the angles are 45

means acutually we have done 90/2 = 45

sp angle b and angle c are 45