Question

0.126g acid requires 20ml 0.1 NaOH for complete neutralisation find equivalent wt of acid

Answer 1

20 ml of 0.1N NaOHneutralize 20 ml of 0.1N acid Weightofacid=0.126g Volume = 20 ml=201000litre Normality = 0.1 N Equivalent weight = ? Equivalentweight=weightofacidN×V =0.126×10000.1×20=63