Question

0.13bar in the form of p/q

Answer 1

$\displaystyle \sf{ 0. \overline{13} } = \frac{13}{99}$

Given :

$\displaystyle \sf{ 0. \overline{13} }$

To find :

To express in p/q form

Solution :

Step 1 of 2 :

Write down the given number

The given number is $\displaystyle \sf{ 0. \overline{13} }$

Step 2 of 2 :

Express in p/q form

$\displaystyle \sf{ Let \: \: x = 0. \overline{13} }$

⇒ x = 0.131313 . . . . . - - - - - (1)

Multiplying both sides by 100 we get

100x = 13.131313 . . . . . - - - - - (2)

Equation 2 - Equation 1 gives

99x = 13

$\displaystyle \sf{ \implies x = \frac{13}{99} }$

$\displaystyle \sf{ \therefore \: \: \: 0. \overline{13} } = \frac{13}{99}$

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Answer 2

Answer:

Let the no. be

:. x = 0.1333

let this be equation

Multiply both sides with 0.1333

10×x=0.1333×10

= 10x = 1.333 let this be equation

Now subtract equation 1 from equation

2

10x -x =1.3333-0.1333

9x= 1.2

remove the decimal and 1.2 will become 12 and 9 will become 9x

:. x =12/90



and on when will reduce the answer is 6/45 and on more further when we will reduce it the answer is 2/15

Ans- 2/