0.16g of dibasic acid require 25ml decimolar NaoH sol for complete neuralisation .the molecular mass of acid is
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We begin by defining some core terms.
Diabasic — This means for every mole of the acid we have two moles of the base.
Decimolar — Molarity/10 = 0.1 M
Moles of NaOH in 25 ml is :
25/1000 × 0.1 = 0.0025 moles
Moles of the acid is :
0.0025/2 = 0.00125 moles
Mass = moles × molar mass
Molar mass = mass / moles
Molar mass = 0.16/0.00125 = 128 g/mol
Molecular mass : 128g
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