Question

0.17: Calculate the gravitational force between a 10 kg ball and a 20 kg ball
placed at a separation of 5 m
(2)​

Answer 1

Answer:

F = 53.3 x 10^-11 N

Step-by-step explanation:

Given:

m1= 10kg

m2= 20kg

G= 6.673 x 10^-11Nm^2kg^-2  

r = 5

F = Gm1m2/r²

F = (6.673 x 10^-11 x 10 x 20)/5²

F = 6.673 x 8 x 10^-11

F = 53.3 x 10^-11 N

Answer 2

we know F=G×m1×m2/r^2

m1=10

m2=20

r=5

G=6.67×10^-11

so F=(6.67×10^-11)×10×20/5×5

F=(6.67×10^-11)×8

F=53.36×10^-11

so F=5.336×10^-10

I hope this helped you