0.196g of an organic compound determine the '/, of sulphur
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mass of substance taken =0.136g
mass of BaSo4 formed = 0.466g
molecular mass of BaSO4 =137+32+64=233
mass of sulphur in 0.466g BaSo4 =
0.466 X 32/233g
percentage of S in the compound =
0.466 X 32/233 X 100/0.136=20.25
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mass of BaSo4 formed = 0.466g
molecular mass of BaSO4 =137+32+64=233
mass of sulphur in 0.466g BaSo4 =
0.466 X 32/233g
percentage of S in the compound =
0.466 X 32/233 X 100/0.136=20.25
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hey the right answer
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hopes help you
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