0.2 M, 100ml NaOH is mixed wih 0.4 M, 100mL HCl solution . Determine energy released during the reaction : Given H+(aq)OH−(aq)→H2o(l), ΔH=−57.5KJmol−1
Answers
grams of H2O2 will be ...
grams of H2O2 will be ...A 3.4g sample of h2o2 solution containing x% H2O2 by mass requires x ml of a ... 2H2O2(l)⟶2H2O(l)+O2(g)ΔH=−196kJ How many kilojoules are released ... how many grams of HCL is needed to produce 200 grams of hydrogen.. The initial rate of reaction for H2O2(aq) H2O (l) 1/2 O2 (g) is found to be 1.7x10(-3)M/s.
Answer:
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Explanation:
AnswerAnswer
Total heat lost by Ni = (1500 g Ni)(0.44 J/g-°C)(100 °C - Tf)
Total heat gained by H2O = (500 mL)(1g/1mL)(4.184 J/g-°C)(Tf - 21 °C)
Set the two expressions equal to each other and solve for Tf = 40 °C.
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Notice that to calculate the total heat lost by the Ni the final temperature was subtracted from the initial temperature in order to end up with a positive number.
Another way to look at it is to write the expressions for the ΔH of the Ni and for the ΔH of the water and then make the ΔH for the Ni the negative of the ΔH for the water. That is because the Ni gives off heat and the water absorbs the same amount of heat.
ΔHwater = (500 mL)(1g/1mL)(4.184 J/g-°C)(Tf - 21 °C)
ΔHNi = (1500 g Ni)(0.44 J/g-°C)(Tf - 100 °C)
ΔHwater = -ΔHNi then results in the same expressions as above.
Total heat lost by Ni = (1500 g Ni)(0.44 J/g-°C)(100 °C - Tf)
Total heat gained by H2O = (500 mL)(1g/1mL)(4.184 J/g-°C)(Tf - 21 °C)
Set the two expressions equal to each other and solve for Tf = 40 °C.
-------------------
Notice that to calculate the total heat lost by the Ni the final temperature was subtracted from the initial temperature in order to end up with a positive number.
Another way to look at it is to write the expressions for the ΔH of the Ni and for the ΔH of the water and then make the ΔH for the Ni the negative of the ΔH for the water. That is because the Ni gives off heat and the water absorbs the same amount of heat.
ΔHwater = (500 mL)(1g/1mL)(4.184 J/g-°C)(Tf - 21 °C)
ΔHNi = (1500 g Ni)(0.44 J/g-°C)(Tf - 100 °C)
ΔHwater = -ΔHNi then results in the same expressions as above.