Math, asked by dhanrajnaik10, 10 months ago

(0.22)⁴×(0.222)³÷(0.2)⁵×(0.2222)²

Answers

Answered by harendrachoubay
1

The value of (0.22)^{4} × (0.222)^{3} ÷ (0.2)^{5}  × (0.2222)^{2} is "10^{ 13} ×  \frac{22^{ 4} × 222^{ 3} }{22^{5} × 222^{2} }".

Step-by-step explanation:

We have,

(0.22)^{4} × (0.222)^{3} ÷ (0.2)^{5}  × (0.2222)^{2}

= (\frac{22}{100} )^{4} ×  (\frac{222}{1000} )^{3} ÷

(\frac{2}{10} )^{5} × (\frac{2222}{10000} )^{2}

= \frac{10^{ - 4} × 10^{ - 3} }{10^{ - 5} × 10^{ - 15} } ×

\frac{22^{ 4} × 222^{ 3} }{22^{5} × 222^{2} }

= 10^{ - 7 + 20} ×  \frac{22^{ 4} × 222^{ 3} }{22^{5} × 222^{2} }

= 10^{ 13} ×  \frac{22^{ 4} × 222^{ 3} }{22^{5} × 222^{2} }

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