Question

0.24 mole of A2 was completely dissociated to give A which gives C on reaction with excess of B. How many miles of C were produced? A2➡️2A A+B➡️3C

Answer 1

Answer: 1.44 moles of C will be produced.

Explanation:

We are given:

Moles of $A_2$ = 0.24 moles

• For the given chemical reaction:

$A_2\rightarrow 2A$

By Stoichiometry of the reaction:

1 mole of $A_2$ is producing 2 moles of A.

So, 0.24 moles of $A_2$ will produce = $\frac{2}{1}\times 0.24=0.48mol$ of A.

• For the given chemical reaction:

$A+B\rightarrow 3C$

B is present in excess. So, it is considered as an excess reagent.

A is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of A is producing 3 moles of C.

So, 0.48 moles of A will produce = $\frac{3}{1}\times 0.48=1.44mol$ of C.

Hence, 1.44 moles of C will be produced.

Answer 2

Answer:

Ans is 1.44 moles

Explanation:

• See the attachment for ans.