Question

0.25 M solution of NaCl contain 29.25g of NaCl in...

Answer 1

Molar mass NaCl = 58.5g/mol 
0.25mol = 58.5*0.25 = 14.625g 
You have 29.25g NaCl 
volume for a 0.25M solution = 29.25/14.625*1000 = 2000mL 

Answer 2

Molarity = (moles of solute/NaCl)/volume of solution
moles of NaCl = (mass of NaCl)/molar mass of NaCl
=> moles of NaCl =29.25/58.5 = 1/2 = 0.5
And Molarity = 0.25 M (given)
so, Volume of solution = (moles of solute/NaCl)/Molarity
=> Volume of solution = 0.5/0.25
=> volume of solution = 2 Litre....

So, 0.25 M solution of NaCl contain 29.25g of NaCl in 2 litre solution...