Question

0.262 to grams of substance give ones combustion 0.361 grams of co2 and 0.147 grams of H2O what is empirical formula of the substance ​

Answer 1

Answer:

44 g of CO2 contains 12 g of CSo, 0.361 g of CO2 contains 1244×0.361=0.098 g of CSimilarly,18 g of H2O contains 2 g of HSo, 0.147 g of H2O contains 218×0.147=0.016 g of HSo, amount of O = 0.262−0.098−0.016 =0.148 g of O% of C=0.0980.262×100=37.40% of H=0.0160.262×100=6.10% of O=0.1480.262×100=56.48%atomic weight of C=37.4012=3.11%atomic weight of H=6.101=6.10%atomic weight of O=56.4816=3.53C : H : O = 3.11 : 6.10 : 3.53 ≈ 1:2:1So, empirical formula = CH2OHence, correct answer is (1)

Explanation:

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Answer 2

Explanation:

धन्यवाद बोलो तुम क्या तुम बोले शाम एमपी ग्राम सौंफ सब्सटेंस गिव वंश कमीशन ग्रामसभा व्हाट इज एंड रिकॉग्निशन नीचे दिए गए प्रश्नों के उत्तर लिखिए