Question

0.27 g of a long chain fatty acid was dissolved in 100 cm³ of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer?
[Density of fatty acid = 0.9 g cm⁻³
, π = 3]
(A) 10⁻⁴ m (B) 10⁻⁸ m
(C) 10⁻² m (D) 10⁻⁶ m

Answer 1

$\huge\bold{Answer}$

Option (D)

10^-6 m......

Answer 2

Answer:

D. will be correct answers

Explanation:

10^-6