Question

0.2g of NaOH is dissolve in water and volume is made up to 500ml. Calculate molarity

Answer 1

Answer:

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Explanation:

The molecular weight of NaOH is 40 g/mol.

The number of moles of NaOH 40 g/mol5 g=0.125 moles.

500 ml water corresponds to0.500 L.

The molarity of the solution =0.500 L0.125 moles=0.25 M.

Answer 2

Answer:

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Class 12

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>>Amount of sodium hydroxide present in 50

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Amount of sodium hydroxide present in 500ml of 0.2M solutions is :

Medium

Solution

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Correct option is A)

Molarity (M) : The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.

Molarity of a solution

(M)=

molar mass of solute

mass of solute

×

volume of solution in mL

1000

∴0.2=

40

w

×

500

1000

so w=4gm.

Amount of sodium hydroxide present in 500ml of 0.2M solutions is 4 gm.