Question

0.2x+0.3y=1.3
0.4x+0.5y=2.3

Answer 1

2(0.2x+0.3y)=2.6
=0.4x+0.6y=2.6
then,do subtraction
0.4x+0.6y=1.3
0.4x+0.5y=2.3
0.1y=-1
y=-10
0.4x+0.5×(-10)=2.3
0.4x+(-5)=2.3
0.4x=2.3+5.0
x=7.3/0.4
x=18.25

Answer 2

Answer:

$\huge{\pink{\boxed{\green{\sf{\therefore x=2}}}}}$

$\huge{\pink{\boxed{\green{\sf{\therefore y=3}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

$\: \: \: \: \: \: \: \: \: { \orange{given}} \\{ \pink{ \boxed{ \green {0.2x - 0.3y = 1.3}}}} \\{ \pink{ \boxed{ \green {0.4x - 0.5y= 2.3}}}} \\ \\ { \blue{to \: find}} \\ {\purple{ \boxed{ \red {x = ?}}}} \\ {\purple{ \boxed{ \red {y =?}}}}$

☆ According to given question:

☆ Using Substitution method:

$\to 0.2x + 0.3y = 1.3 \\ \to 0.2x = 1.3 - 0.3y \\ \to x = \frac{1.3 - 0.3y}{0.2} - - - - - (1) \\ \\ \to 0.4x + 0.5y = 2.3 - - - - - (2)\\ substituting \: value \: of \: x \: in(2) \\ \to 0.4\times (\frac{1.3 - 0.3y}{0.2} ) + 0.5y = 2.3 \\ \to 2.6 - 0.6y + 0.5y = 2.3 \\ \to 2.6 - 2.3 = 0.1y \\ \to 0.1y = 0.3 \\ { \pink{ \boxed{ \green{\therefore y = 3}}}} \\ \\ \to putting \: value \: of \: y \: in \: (1) \\ \to x = \frac{1.3 - 0.3 \times 3}{0.2} \\ \to x = \frac{1.3 - 0.9}{0.2} \\ \to x = \frac{0.4}{0.2} \\ { \pink{ \boxed{ \green{\therefore x = 2}}}}$

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