Question

0.2x + 0.3y =1.3 and 0.4x + 0.5y =2.3 by substitution method

Answer 1

Answer:

x=2;y=3

Step-by-step explanation:

0.2x+0.3y=1.3

(0.2x+0.3y)×10=1.3×10

2x+3y=13 ---[1]

0.4x+0.5y=2.3

(0.4x+0.5y)5=2.3×5

2x+2.5y=11.5 ---[2]

Eq. [1]-[2]

2x+3y-2x-2.5y=13-11.5

0.5y=1.5

5y=15

y=3

x=(13-3y)/2=(13-3×3)/2=2

i hope it helps.

Answer 2

Answer:

answer  ⇒ x=2 ,y=3

Step-by-step explanation:

0.2x+0.3y=1.3-----------------------------------(i)

x=1.3-0.3y/0.2-----------------------------------(ii)

putting value of x we got from first equation in second ,we get,

0.4×1.3-0.3y/0.2+0.5y=2.3

2(1.3-0.3y)+0.5y=2.3

2.6-0.1y=2.3

2.6-2.3=0.1y

y=3

x=1.3-0.9/0.2

x=2