Question

(0.2x+ 0.3y)^2 Find this value

Answer 1

(0.2x)^2+(0.3y)^2+2×0.2x×0.3y

0.4x^2+0.9y^2+0.12xy

Answer 2

Answer:

0.04x² + 0.12xy + 0.09y²

Step-by-step explanation:

using identity (a+b)² = a² + 2ab + b²

where, a = 0.2x

b = 0.3y

therefore, (0.2x + 0.3y)² = (0.2x)² + 2(0.2x)(0.3y) + (0.3y)²

= 0.04x² + 0.12xy + 0.09y²