0.32 bar on 32 in fraction form
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Let x = 0.32 bar -----(1)
100x = 32.32 bar -----(2)
On dividing equation 1 from 2, we get
99x = 32
=> x = 32/99
Required fraction = 32/99
100x = 32.32 bar -----(2)
On dividing equation 1 from 2, we get
99x = 32
=> x = 32/99
Required fraction = 32/99
jasdishsingh:
I want to confirm my answer but thanks
ur welcome brother :)
Mention not ok thanx again thankuuuu a lot brother
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