Question

0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal:. please solve the law of equivalence

Answer 1

Answer:

Explanation:

Given,

Mass of metal=0.32g

Volume of hydrogen=112ml

=112×10  

−3

L

Now we know,

Equivalent Weight of metal is the mass of metal required to produce 1gm of Hydrogen ⟶(1)

Now, We know 1 mole of hydrogen= 22.4L of H  

2

​  

 

⇒ If 0.32g Metal produces 112×10  

−3

L of H  

2

​  

 

∴ Mass of mass metal required to produce 11.2L of H  

2

​  

 

[∵1gmH  

2

​  

=11.2L of H  

2

​  

]=  

112×10  

−3

 

0.32×11.2

​  

=32gm

∴ From (1) Equivalent weight of metal= 32gm