Question

0.4-0.167 with process

Answer 1

0.4-0.167 = 0.233

(3) (9) (10)
1) 0.4
- 0.1 6 7
When we subtract like this take carry above above 37- it will come ( 10) and above 6- it will come (9) and the last 4- will become( 2) as we have given carries further..

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Answer 2

Answer:

Required answer is 0.233.

Step-by-step explanation:

Given,

$(0.4 - 0.167)$

Here two numbers are decimal number and we want to subtract them.

By Decimal Subtraction rule,we can write,

$0.4 - 0.167 \\ = 0.233$

Note: decimal subtraction rule completely same as normal subtraction but here we need to remember about possible of the point.

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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