0.4 grams of NaOH is added to 100 ml of 0.1 M NaOH solution and the volume of
solution is made to 200ml by adding water. Calculate the molarity of the resulting
solution
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Answered by
5
Answer:
NaOH+CH
3
COOH⟶CH
3
COONa+H
2
O
10 m mol 20 m mol
0 10 m mol 10 m mol
Now it is a buffer
pH=pk
a
+log[
acid
salt
]
pH=4.74+log1=4.74
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