A 20 G of impure sample nahco3 on heating gave 2.27 litre carbon dioxide at STP calculate the percentage purity of the sample
Answers
Answer:
50
Sodium bicarbonate decomposes in
the following manner.
2NaHCO
3
→Na
2
CO
3
+H
2
O+CO
2
Sodium Carbonate is stable and
doesn't dissociate upon normal
heating.
Vol. of CO
2
=224ml
22.4Ltr=1mole
So moles of CO
2
=0.224/22.4=0.01mole
0.01mole=44×0.01g=0.44g
1 mole CO
2
is procured by 2 mole NaHCO
3
∴ Moles of NaHCO
3
=2×0.01=0.02
=0.02×84=1.689
% age =
Totalmass
mass
×100=
2
1.68
×100=84%
Answer:
Sodium bicarbonate decomposes in
the following manner.
2NaHCO
3
→Na
2
CO
3
+H
2
O+CO
2
Sodium Carbonate is stable and
doesn't dissociate upon normal
heating.
Vol. of CO
2
=224ml
22.4Ltr=1mole
So moles of CO
2
=0.224/22.4=0.01mole
0.01mole=44×0.01g=0.44g
1 mole CO
2
is procured by 2 mole NaHCO
3
∴ Moles of NaHCO
3
=2×0.01=0.02
=0.02×84=1.689
% age =
Totalmass
mass
×100=
2
1.68
×