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Answered by gauravshrigiri22
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Samples of simulated lake water are exposed to SO2(g). Two graduated cylinders containing samples of simulated lake water had CaCO3(s) added, and dissolves to form Ca2+ ions and CO32- ions. The chemical reaction of water exposed to SO2(g) is:

H2O(l) + S02(g) --> H2S04(aq) (sulphuric acid) , producing Hydronium ions in solution.

Hydronium ions react with the CO32- ions which then produces,

options:

HCO3-(aq) (weak acid)

H2CO3(aq) (weak acid)

HCO3-(aq) (strong acid)

H2CO3(aq) (strong acid)

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