Question

find the zeroes of quadratic polynomial 9x²- 9x - 4 and verify ​

Answer 1

Step-by-step explanation:

Given -

• p(x) = 9x² - 9x - 4

To Find -

• Zeroes of the polynomial and verify the relationship between the zeroes and the coefficient.

Now,

By using quadratic formula :-

• x = -b ± √b² - 4ac/2a

→ x = -(-9) ± √(-9)² - 4×(9)×(-4)/2(9)

→ 9 ± √81 + 144/18

→ 9 ± √225/18

→ 9 ± 15/18

Zeroes are -

→ x = 9 + 15/18

→ x = 24/18

→ x = 4/3

And

→ x = 9 - 15/18

→ x = -6/18

→ x = -1/3

Verification :-

As we know that :-

• α + β = -b/a

→ -1/3 + 4/3 = -(-9)/9

→ -1 + 4/3 = 9/9

→ 3/3 = 9/9

→ 1 = 1

LHS = RHS

And

• αβ = c/a

→ -1/3 × 4/3 = -4/9

→ -4/9 = -4/9

LHS = RHS

Hence,

Verified...

It shows that our answer is absolutely correct.

Answer 2

Answer:

hey mate!

here is ur answer

9x²-9x-4 =0

9x²-(12-3) x-4=0

9x²-12x+3x-4=0

3x(3x-4) +1(3x-4) =0

(3x-4) (3x+1) =0

3x-4=0 3x+1=0

x=4/3 x=-1/3

$\alpha + \beta = - b \div a \\ 4 + 3 + ( - 1 \div 3) \\ 1 = 1 \\ \alpha \beta = c \div a \\ 4 \div 3 \times - 1 \div 3 = - 4 \div 9 \\ - 4 \div 9$

hence verified!!

mark as brainliest plzz❤

#shruti