Question

0.44 g of colour less oxide of nitrogen occupies 224ml at stp the compound is

Answer 1

Need to find molecular mass: 

M = wRT / PV 

M = (0.44 * 0.082 * 273) / (1 * 0.224) = 44 

The compound you are looking for is N2O.

Answer 2

Answer:

The compound is $NO_2$.

Explanation:

Let the compound that is oxide of nitrogen be $NO_x$

Oxide of nitrogen occupies  at STP = 224 mL = 0.224 L

1 mole of gas occupies 22.4 L of volume at STP.

Then 0.224 L of volume will be occupied by:

$\frac{1}{22.4 L}\times 0.224 L=0.01 mol$

$0.01 mol=\frac{0.44 g}{14 g/mol+16 g/mol\times x}</p><p>x = 1.8 ≈ 2</p><p><strong>The compound is [tex]NO_2$.