Question

0.456g of a metal gives 0.606g of its chloride.calculate the equivalent mass of the metal.

Answer 1

et the Symbol of the Metal be M.

Mass of the Metal = 0.456 g.

Mass of the Metallic Chloride = 0.606 g.

Reaction for the Formation of the Metallic Chloride is given below,

2M + Cl₂ ------ 2MCl.

From this Reaction,  

2 mole of the Metals forms two moles of the Metallic Chloride.

Now, Let the molar mass of the Metal be m.

∴ No. of moles of Metal = Mass/Molar mass.

  = 0.456/m

Similarly, No. of mole of Metallic Chloride = Mass/Molar Mass.

Molar mass of the Metallic Chloride = Molar mass of (Metal + Chlorine)

∴ No. of moles of Metallic Chloride = (m + 35.5)

 = 0.606/(m + 35.5)

Since, the number of moles of the metal and the chloride are equal,

∴ 0.456/m = 0.606/(m + 35.5)

∴ 0.456(m + 35.5) = 0.606m

∴ 0.456m + 16.188 = 0.606m

⇒ 0.606m - 0.456m = 16.188

⇒ m = 16.188/0.15

⇒ m = 107.92 g.

Since, the number of the Electrons lost by the Metal is (From the Reaction) , therefore, molar mass will be equal to the Equivalent mass of the metal.

∴ Equivalent mass of the metal is 107.92 g.