Question

(33)
A bus covers a distance from A to B at 40 km/h and while returning it travels at 50 km/h.
calculate the average speed.​

Answer 1

Answer:

45km/h

Step-by-step explanation:

average=40/2+50/2=45

Answer 2

let the distance between A and B be x

Speed ¹ = 40 kph

therefore time taken = x/40

return journey

speed ²= 50 kph

time taken = x/50

total distance traveled =x+x=2x km

displacement =0

average speed = total distance/total time

= 2x/(x/40+x/50)

= 2x÷[ x(50+40)/200]

= 2*200/90

= 45 kph