Question

0.4x + 0.3y = 17 0.7x - 0.2y = 0.8 Substituting method

Answer 1

Hello! Lets solve this!
So, we will start off with the first equation,  and then continue onto the second one :)

0.4x+0.3y=(17)(0.7)x
0.4x+0.3y+−11.9x=11.9x+−11.9x−11.5x+0.3y=0x−11.5x+0.3y+−0.3y=0x+−0.3y−11.5x=0x−0.3y
−11.5x/−11.5=0x−0.3y/−11.5x=0x+0.026087y

The second equation :
-0.2y=0.8
−0.2y/−0.2=0.8/−0.2y=−4

Hope this helped! If you have any other questions or would like further explanation just let me know!! :)

Answer 2

0.4x+0.3y=(17)(0.7)x
0.4x+0.3y+−11.9x=11.9x+−11.9x−11.5x+0.3y=0x−11.5x+0.3y+−0.3y=0x+−0.3y−11.5x=0x−0.3y
−11.5x/−11.5=0x−0.3y/−11.5x=0x+0.026087y

The second equation : 
-0.2y=0.8
−0.2y/−0.2=0.8/−0.2y=−4