Question

0.5 coulombs of charge flows through a conductor in 2 seconds. what is the magnitude of the current flowing through the conductor​

Answer 1

Answer:

Charge flow Q=i×t=0.5×2=1

we know that Q=ne where n is no. of electrons.

So, number of electrons n=

1.6×10

−19

1

= 6.25×10

18

electrons.

Answer 2

Explanation:

Q=It

0.5=I X 2

I= 0.5/2

I= 0.25 Ampere

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