Math, asked by varunkulkarni2905, 2 days ago

0.5) Find Maclaurin's series expansion of
sec^-1 (1/1-2x^2)​

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Answered by kavysiroya276
1

Answer:

I don't know this answer

Answered by sharadaa847
0

Answer:

A Maclaurin series is a function that has expansion series that gives the sum of derivatives of that function. The Maclaurin series of a function f(x) up to order n may be found using Series [f,x,0,n] [ f , x , 0 , n ] .

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