Question

0.5 molal aqueous solution of weak acid is 20% ionized if KF for water is 1.86 K KG mole inverse. what will be the lowering in freezing point of the solution ?
please give right answer if u know ​

Answer 1

∆Tf=iKf m (I=1.20)

= 1.2 × 1.86 × 0.5 = 1.12 K

hope it will help u ✌✌

Answer 2

ans is 1.112K..........