The radii of two circles are 8 meters and 6 meters.find the circumference the circle whos areas is equal to the some of areas of these 2 circles.
Ans . 62.85
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Area of the circle whose radius is 8 meters = πr^2 = 22/7 × 8 ×8 = 201.14 sq. meters.
And area of the circle whose radius is 6 meters = πr^2 = 22/7 × 6 × 6 = 113.14 sq. meters.
Sum of the area of the both circles = 201.14 sq. meters = 113.14 sq. meters = 314.28 sq. meters.
Now, the area of the circle whose area is equals to the sum of these two circles = 314.28 sq. meters.
= πr^2 = 314.28 sq. meters.
=22/7 r^2 = 314.28 sq. meters.
= r^2 = 314.28 ×7/22
= r^2 = 99.99 sq. meters. (approx 100)
= r = 10 meters.
Now, circumference = 2πr
= (2 × 22/7 × 10 ) meters
= 440/7 meters
= 62.85 meters Ans
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And area of the circle whose radius is 6 meters = πr^2 = 22/7 × 6 × 6 = 113.14 sq. meters.
Sum of the area of the both circles = 201.14 sq. meters = 113.14 sq. meters = 314.28 sq. meters.
Now, the area of the circle whose area is equals to the sum of these two circles = 314.28 sq. meters.
= πr^2 = 314.28 sq. meters.
=22/7 r^2 = 314.28 sq. meters.
= r^2 = 314.28 ×7/22
= r^2 = 99.99 sq. meters. (approx 100)
= r = 10 meters.
Now, circumference = 2πr
= (2 × 22/7 × 10 ) meters
= 440/7 meters
= 62.85 meters Ans
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