0.5 mole of gas at temp 300 K expands
isothermally from an initial volume of 2.0L
to final volume of 6.0L. (a) What is the work
done by the gas ? (R = 8.31 J mol" K-),
(b) How much heat is supplied to the gas?
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Step-by-step explanation:
Solution: (a) The work done in isothermal
expansion is W = nRTln
V/Vfi
Where n = 0.5, Vf
= 6L, Vi
= 2L
W = 0.5 mol
8 319 300 62K
.ln mol
K L/L
= 1.369 kJ.
(b) From the first law of thermodynamics,
the heat supplied in an isothermal process
is spent to do work an a system. Therefore,
Q = W = 1.369 kJ.
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