Question

0.5 mole of gas at temp 300 K expands
isothermally from an initial volume of 2.0L
to final volume of 6.0L. (a) What is the work
done by the gas ? (R = 8.31 J mol" K-),
(b) How much heat is supplied to the gas?​

Answer 1

Step-by-step explanation:

Solution: (a) The work done in isothermal

expansion is W = nRTln

V/Vfi

Where n = 0.5, Vf

= 6L, Vi

= 2L

W = 0.5 mol

8 319 300 62K

.ln mol

K L/L

= 1.369 kJ.

(b) From the first law of thermodynamics,

the heat supplied in an isothermal process

is spent to do work an a system. Therefore,

Q = W = 1.369 kJ.

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