Question

0 52. A body A moves with a uniform acceleration a and zero initial velocity. Another body B. Starts from the same point moves in the same direction with a Constant velocity v. The two bodies meet ofter a time t The value of t is a)2v/a b ) v/a c) v/2a d)√v/2a​

Answer 1

Answer:

A

Explanation:

Position of A     $S_{A}$ =ut× 1/2a$t^{2}$=1/2a$t^{2}$

Position of B     $S_{B}$ =vt

when they met ,

   $S_{A}$  =$S_{B}$

   $\frac{1}{2}$a$t^{2}$  =vt

   t=$\frac{2V}{a}$     Answer