0.54 gm of metal "M" yields 1.02 gm of its oxide M203 the atomic weight of metal M is.
give soln....
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Answered by
6
Answer:
Let the mass of M be x. so mass of M2O3=2x+48
now write reaction
4M+3O2=2M2O3.
so 2 moles of M will make 1 mole of M2O3
now moles of M given are 0.56/x and that of M2O3 are 1.02/(2x+48)
So we know that moles of M should be double of moles of M2O3
therefore (0.56/x)=2(1.02/(2x+48))
giving us X =24..
Hope it helps you....
itzdiya❤_❤
Answered by
7
hi mate here is ur answer
=====
Explanation:
Let the mass of M be x. so mass of M2O3=2x+48
now write reaction
4M+3O2=2M2O3.
so 2 moles of M will make 1 mole of M2O3
now moles of M given are 0.56/x and that of M2O3 are 1.02/(2x+48)
So we know that moles of M should be double of moles of M2O3
therefore (0.56/x)=2(1.02/(2x+48))
giving us X =24..
******Gm eq of metal = grm eq. Of M and O********
=======
hope it is helpfull
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