Question

0.5A current has been flowing in a circuit for 20minutes. Calculate the number of electrons flowing from one end to other end of the circuit?

Answer 1

Answer:

Hence, number of electrons =

374.531835206 × 10^(19)

Explanation:

We know that,

Current, I = Charge, q / Time, t

=> I = q / t

Also we know that,

Charge, q = No. of electrons ,n × charge of each electron, e

=> q = ne

By applying the values, in the formula, we get,

=> I = ne / t

Here, given,

I = 0.5 A

t = 20 minutes = 1200 seconds

n = 1.602 × 10^(-19)

By applying the values in equation, we get,

=> 0.5 = n × 1.602 × 10^(-19) / 1200

=> n = 0.5 × 1200 × 10^(19) / 1.602

=> n = 374.531835206 × 10^(19)

Hence, number of electrons =

374.531835206 × 10^(19)