Question

0.6% (w/v) solution of urea would be isotonic with

Answer 1

here molarity of given data i.e.0.6% solution urea=0.1 M

by d formula M=10x/Mol Wt.       (x=given %)

i.e. 0.6*10/60

now verifiy wid d given options....  0.1 M gulcose is isotonic.

KCl is ionic so it dissociates and 0.6% glucose=0.03 M

 

i hope its correct...:)

Answer 2

Answer:

Explanation:

0.6 has molarity=\dfrac{0.6}{60} \times \dfrac{1000}{100}=0.1=  

60/0.6 ×  100/1000 =0.1

As, KCl is ionic it dissociates and  

0.6%0.6 glucose=0.3 M=0.3M