Question

0.63 g sodium carbonate neutralizes 50 mL hydrochloric acid solution. Calculate the concentration of hydrochloric acid in normality and molarity.
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Answer 1

Answer:

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Correct option is B)

HCl+NaOH→NaCl+H

2

O

In this chemical reaction, the molar ratio is 1:1 between HCl and NaOH.

So, moles of HCl = moles of NaOH

M

HCl

× Volume of HCl = M

NaOH

× Volume of NaOH

M

HCl

=

volumeofHCl

M

NaOH

×volumeofNaOH

M

HCl

=

50.00ml

25.00ml×1.00M

M

HCl

=0.50MHCl

So, the concentration of HCl is 0.50M