Question

0.6g of urea on treatment with excess Hno2(aq) solution liberates​

Answer 1

0.6 g of urea on treatment with excess HNO2 (aq) solution liberates​ 0.28 gm N2, 0.44 gm CO2 and 0.54 gm H2O.

- The reaction of urea with HNO2 is given as:

NH2CONH2 + 2HNO2 ---> 2 N2 + CO2 + 3 H2O

⇒ 60 gm urea liberates 28 g N2, 44 gm CO2 and 54 gm H2O

⇒ When 0.6 gm urea is reacted with excess HNO2, then:

- Amount of  N2 liberated = (28/60) × 0.6 = 0.28 gm

- Amount of CO2 liberated = (44/60) × 0.6 = 0.44 gm

- Amount of H2O formed = (54/60) × 0.6 = 0.54 gm

Answer 2

Answer:

0.6 g of urea on treatment with excess HNO2 (aq) solution liberates​ 0.28 gm N2, 0.44 gm CO2 and 0.54 gm H2O.

- The reaction of urea with HNO2 is given as:

NH2CONH2 + 2HNO2 ---> 2 N2 + CO2 + 3 H2O

⇒ 60 gm urea liberates 28 g N2, 44 gm CO2 and 54 gm H2O

⇒ When 0.6 gm urea is reacted with excess HNO2, then:

- Amount of  N2 liberated = (28/60) × 0.6 = 0.28 gm

- Amount of CO2 liberated = (44/60) × 0.6 = 0.44 gm

- Amount of H2O formed = (54/60) × 0.6 = 0.54 gm

PLEASE MARK ME AS BRAINLIEST

PLEASE PLEASE