Question

0.7 moles of potassium sulphate is allowed
to react with 0.9 moles of barium chloride in
aqueous solutions. The number of moles of
the substance precipitated in the reaction is​

Answer 1

Answer:

the moles of precipitate formed is 0.7 moles

Answer 2

Explanation:

BaCl2 +K2SO4=BaSo4+2KCl

here sulfate ions are the limiting reagent so0.4moles of k2so4 will react with 0.4 moles of BaSO4 to form 0.4 moles of k2so4 and BaSO4