0.72 gm of an oxide of a metal m on reduction with { h }_{ 2 } gave 0.64 g of the metal. The atomic weight of the metal is 64. The empirical formula of the compound is?
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0.72 gm of an oxide of a metal m on reduction with { h }_{ 2 } gave 0.64 g of the metal. The atomic weight of the metal is 64. The empirical formula of the compound is?
Answer: As we know that Equivalent weight =(weight of metal/weight of oxygen)×8 =320.4×8=64; Vapour density =mol.
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