0-9. Arvind is eight years older than his sister. In three years he will be twice as old as his
sister. How old are they now?
Answers
Given that,
Arvind is 8 yrs older than his sister.
Let the present age of his sister be x.
Therefore his present age = x + 8
ATQ,
After 8 years, Arvind will be twice as old has his sister will be.
➡ (x + 8) + 3 = 2(x + 3)
➡ x + 11 = 2x + 6
➡ x - 2x = 6 - 11
➡ -x = -5
➡ x = 5
Hence, the present ages of :-
- Arvind's sis = x = 5 years
- Arvind = x + 8 = 13 years
VERIFICATION :-
Arvind's age must be twice as his sister's age after 8 years.
LHS :-
» 2(Arvind's sister's age after 3 years)
= 2(5 + 3)
= 2(8)
= 16 years
» Arvind's age after 3 years
= 13 + 3
= 16 years
LHS = RHS. Hence verified!
AnswEr :
☑ Given :
• Arvind is Eight Yrs Old than his Sister.
• In 3 Yrs He will be twice as Old as his Sister.
☑ To Find :
• There Present Age.
☑ Solution :
- Arvind's Sister Present Age = x Yrs
- Arvind's Present Age = (x + 8) Yrs
☢ After 3 Yrs :
» Arvind's Sister Age = (x + 3) Yrs
» Arvind's Age = (x + 8) + 3 = (x + 11) Yrs
☢ A.T.Q.
➟ Arvind's Age = 2 × Arvind's Sister Age
➟ (x + 11) = 2 × (x + 3)
➟ x + 11 = 2x + 6
➟ 11 - 6 = 2x - x
➟ x = 5 Yrs
━━━━━━━━━━━━━━━━━━━━━━━━
▣ Arvind's Sister Age = x Yrs
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 5 Yrs
▣ Arvind's Age = (x + 8) Yrs
⠀⠀⠀⠀⠀⠀⠀⠀ ⠀= (5 + 8) Yrs