0.9%sodium chloride solution is good and balanced to RBC. A lab technician accidentally places a sample of RBC in 1.8%sodium chloride solution.what happens ? Why ?
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0.9 sodium chloride solution is said to be an isotonic solution to the concentration of the cytoplasm of the red blood cell. This means when placed in a sodium chloride of the concentration there will be no net change in the content of the cytoplasm of the red blood cells,
On the other hand, a sodium chloride solution of 1.8% is hypertonic to the red blood cell's cytoplasm concentration - this means that water molecules will move out of the red blood cytoplasm and into the 1.8% of sodium chloride by osmosis and become flaccid.
Here is a similar question I answered here on brainly:
https://brainly.in/question/1385985
On the other hand, a sodium chloride solution of 1.8% is hypertonic to the red blood cell's cytoplasm concentration - this means that water molecules will move out of the red blood cytoplasm and into the 1.8% of sodium chloride by osmosis and become flaccid.
Here is a similar question I answered here on brainly:
https://brainly.in/question/1385985
narendramodi157:
was helpful
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