Question

0.92 gram of AG2C03 is heated strongly beyond its melting point after heating the amount of Residue is--- (if atomic mass of silver is 108 gram)

Answer 1

Answer: 0.72 g of Ag is formed.

Explanation:

$2Ag_2CO_3(s)\rightarrow 4Ag(s)+2CO_2(g)+O_2(g)$

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

According to stochiometry:-

2 moles of $Ag_2CO_3$ produces 4 moles of $Ag$

$2\times 276=552g$ of $Ag_2CO_3$ produces $4\times 108=432g$ of $Ag$

0.92 g of $Ag_2CO_3$ produces =$\frac{432}{552}\times 0.92=0.72g$ of $Ag$