Question

0. An object of length 4 cm is placed in front of a concave mirror at distance 30 cm. The focal length of mirror is
15 cm. What will be the length of image?

Answer 1

Answer:

hi= -4cm

u= -30 cm

f= 15 cm

1/f=1/u+1/v

1/15=1/-30+1/v

1/15-1/-30=1/v

1/15+1/30=1/v

2+1/30=1/v

3/30= 1/v

1/10 =1/v

v= -10 cm

Explanation:

m=-v/u

=-10/-30

m=1/3

m=hi/ho

1/3=hi/4

hi=4/3

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Answer 2

Answer: The relationship between the radius of curvature and focal length is that the radius of curvature is twice the focal length. In this case, focal length of the concave mirror is given as 15 cm. Hence, the radius of curvature is 15×2=30cm.

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