Question

(0)
Find second and third term of an A.P. whose first term is - 2
and common difference is -2.​

Answer 1

Answer:

Step-by-step explanation:

Given that,

First term = a = -2

difference = d = -2

For an A.P.

Second term $a_{2}$ = a + d = -2 + (-2) = -4

third term $a_{3}$ = a + 2d = -2 + 2(-2) = -2 - 4 = -6

Answer 2

Answer:

-2 and -6

Step-by-step explanation:

let

a=-2 and d=-2 ('a' is first term and 'd' is common difference)

tn is nth term

tn=[a+(n-1)d]

t2 = [-2+(2-1)(-2)] = -4

t3= [-2+(3-1)(-2)] = -6