Question

0. Find the simple interest on Rs. 2000 in 3 years and 8 months at the rate of 6% per annum.​

Answer 1

Answer:

Given :-

• A sum of Rs 2000 in 3 years and 8 months at the rate of 6% per annum.

To Find :-

• What is the simple interest.

Formula Used :-

$\clubsuit$ Simple Interest or S.I Formula :

$\footnotesize\mapsto \sf\boxed{\bold{\pink{S.I =\: \dfrac{P \times R \times T}{100}}}}$

where,

• S.I = Simple Interest
• P = Principal
• R = Rate of Interest
• T = Time

Solution :-

First we have to convert the time :

$\implies \sf Time =\: 3\: years\: and\: 8\: months$

$\implies \sf Time =\: 3 + \dfrac{8}{12}$

$\implies \sf Time =\: \dfrac{36 + 8}{12}$

$\implies \sf Time =\: \dfrac{\cancel{44}}{\cancel{12}}$

$\implies \sf\bold{\purple{Time =\: \dfrac{11}{3}\: years}}$

Now, we have to find the simple interest :

Given :

• Principal = Rs 2000
• Rate of Interest = 6% per annum
• Time = 11/3 years

According to the question by using the formula we get,

$\longrightarrow \sf S.I =\: \dfrac{2000 \times 6 \times \dfrac{11}{3}}{100}$

$\longrightarrow \sf S.I =\: \dfrac{\cancel{12000} \times \dfrac{11}{\cancel{3}}}{100}$

$\longrightarrow \sf S.I =\: \dfrac{4000 \times 11}{100}$

$\longrightarrow \sf S.I =\: \dfrac{440\cancel{00}}{1\cancel{00}}$

$\longrightarrow \sf S.I =\: \dfrac{440}{1}$

$\longrightarrow \sf\bold{\red{S.I =\: Rs\: 440}}$

${\small{\bold{\underline{\therefore\: The\: simple\: interest\: is\: Rs\: 440\: .}}}}$