Question

0.Find the values of k for which the following equation has equal roots:
(k - 12)x2 + 2(k-12)x+2 = 0​

Answer 1

hey buddy,

here is your answer..

Answer:

K = 12, 14

Step-by-step explanation:

$(k - 12) {x}^{2} + 2(k - 12)x + 2 = 0 \\ d = {b}^{2} - 4ac = 0 \\ = (2k - 24) {}^{2} - 4(k - 12)(2) = 0 \\ = 4k {}^{2} + 576 - 96k - 8k + 96 = 0\\ = 4k {}^{2} - 104k + 672 = 0 \\ \: \: \: \: \: \: \: \: \: \: \: divide \: by \: 4 \\ = k {}^{2} - 26k + 168 = 0 \\ = k {}^{2} - 12k - 14k + 168 = 0 \\ = k(k - 12) - 14(k - 12) = 0 \\ = (k - 14)(k - 12) = 0 \\ k = 14 \: \: and \: \: 12$

I hope it helps you

thank you

good night..✌☺❤